Directory:Derek Elder/Programs/Quadratic Formula
MyWikiBiz, Author Your Legacy — Thursday November 07, 2024
Jump to navigationJump to search#include <iostream> #include <cmath> using namespace std; double sqrt(int discrim) { return sqrt(double(discrim)); } int main() { int A = 0; int B = 0; int C = 0; cout<<"Please enter a value for A: "; cin>>A; cout<<"Please enter a value for B: "; cin>>B; cout<<"Please enter a value for C: "; cin>>C; double discrim = sqrt((B * B) - 4 * A * C); double imaginary_discrim = sqrt(-((B * B) - (4 * A * C))); if(discrim >= 0) { cout<<"The value of the discriminant is: "<<discrim<<"\n"; } else { cout<<"The value of the discriminant is: "<<imaginary_discrim<<"i"<<"\n"; } if(A != 0) { if(A < 0) { A *= -1; } if (discrim > 0) { cout<<"When A = "<<A<<", B = "<<B<<", and C = "<<C<<", the two real solutions are:"<<"\n"; cout<<"X = "<<((-B + discrim)/(2.0 * A))<<"\n"; cout<<"X = "<<((-B - discrim)/(2.0 * A))<<"\n"; } else if (discrim == 0) { cout<<"When A = "<<A<<", B = "<<B<<", and C = "<<C<<", the one real solution is:"<<"\n"; cout<<"X = "<<(-B/(2.0 * A))<<"\n"; } else { cout<<"When A = "<<A<<", B = "<<B<<", and C = "<<C<<", the two imaginary solutions are:"<<"\n"; cout<<"X = "<<(-B/(2.0 * A))<<" + "<<(imaginary_discrim/(2 * A))<<"i"<<"\n"; cout<<"X = "<<(-B/(2.0 * A))<<" - "<<(imaginary_discrim/(2 * A))<<"i"<<"\n"; } } else cout<<"There is no solution for the equation when A = 0."<<"\n"; return 0; }